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2/3x^2=324
We move all terms to the left:
2/3x^2-(324)=0
Domain of the equation: 3x^2!=0We multiply all the terms by the denominator
x^2!=0/3
x^2!=√0
x!=0
x∈R
-324*3x^2+2=0
Wy multiply elements
-972x^2+2=0
a = -972; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-972)·2
Δ = 7776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7776}=\sqrt{1296*6}=\sqrt{1296}*\sqrt{6}=36\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{6}}{2*-972}=\frac{0-36\sqrt{6}}{-1944} =-\frac{36\sqrt{6}}{-1944} =-\frac{\sqrt{6}}{-54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{6}}{2*-972}=\frac{0+36\sqrt{6}}{-1944} =\frac{36\sqrt{6}}{-1944} =\frac{\sqrt{6}}{-54} $
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